A fortune teller has a unique way of predicting his customer’s prognosis. He has three parrots kept in three different cages. Each cage has three cards with a one digit non-zero number inscribed on every card. No two cards have the same number and no cage contains two cards with the number totaling ten. Further the total of numbers on the three cards in the first cage is greater by two than that in the second and by four than that in the third. When a customer asks for his prognosis, the fortune teller lets out the three parrots, which randomly pick one card out of their respective cages. Before the prognosis is made, the fortune teller totals the numbers on the three cards picked out by the parrots and charges the customer the same number of rupees as the total of the numbers on the cards. One day a customer paid seven rupees for his prognosis.

Which of the following combinations of cards may be picked for prognosis?

(a) 5, 7, 8
(b) 7, 9, 4
(c) 2, 6, 3
(d) 1. 3, 8
(e) None of these

• Ans : None of these
  since fortune teller charges amount equals to the sum of the three cards picked by 3 parrots from 3 different cages
  and the customer paid seven rupees which does not satisfy the given condition.
• 10 years agoHelpfull: Yes(26) No(2)
• Ans : None of these
  since fortune teller charges amount equals to the sum of the three cards picked by 3 parrots from 3 different cages
  and the customer paid seven rupees which does not satisfy the given condition.
• 10 years agoHelpfull: Yes(3) No(1)
• considering the cages named as A B and C
  according to the given conditon A=2B and A=4C
  the customer paid the amount as the sum of three cards ,i,e card A,card B and card C=7
  A+B+C=7 so, A+(A/2)+(A/4)=7
  
  Solving, we get A=4
  therefore a,b,c=4,2,1
• 9 years agoHelpfull: Yes(0) No(2)