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A sum of Rs. 350 made up of 110 coins, which are of either Re.1 or Re.5 denomination. How many coins are of Re.1?
Read Solution (Total 17)
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- 1x+5y= 350
x+y=110
solving the two quations we get x= 50, y= 60 coins. - 10 years agoHelpfull: Yes(38) No(1)
- Rs.1 coins= 50 ;50*1=50
Rs.5 coins=60 ; 60*5=300
Total=50+300=350
So total Rs.1 coins are 50 - 10 years agoHelpfull: Yes(6) No(0)
- Let the coin of 1 Re=x
then the coin of 5 Re.=(110-x)
x+5*(110-x)=350
then x=50
so the coin of 1 re.=50 - 10 years agoHelpfull: Yes(3) No(0)
- let x no. of Re.1 coin are present then remaining (110-x) no. of coins are of Re.5
1(x)+5(110-x)=350
x=50 - 9 years agoHelpfull: Yes(1) No(0)
- if the above question is faultless then thee could be an infinite number of solution as 1x + 5y = 350 .
where x and y are integer values .Let x= 5 than y= 69. - 10 years agoHelpfull: Yes(0) No(3)
- 50(1)+60(5) = 350
1 rupee coins are 50. - 10 years agoHelpfull: Yes(0) No(0)
- 60*5+50*1=350 and coin of rs 1 is 50.
- 10 years agoHelpfull: Yes(0) No(0)
- 50=re 1
60=re 5 - 10 years agoHelpfull: Yes(0) No(0)
- Ans. 50 1 re. coins.
5*60+1*50=350 - 10 years agoHelpfull: Yes(0) No(0)
- 1 rupee coin=50
5 rupee coin=60 - 10 years agoHelpfull: Yes(0) No(0)
- sum up of 110 coins from either 1 0r 5 that is
x=y=110
from 1*x+5*y=350
solve both the equations.....
fetting x=50 and y=60..... - 10 years agoHelpfull: Yes(0) No(0)
- 50 coins
5*60=300
remaining 50 rs
1*50 = 50
total 110 coins and 350 rs - 10 years agoHelpfull: Yes(0) No(1)
- Let number of Re1 coins be x and no of Re5 coins be y
x+y=110
by question,
x*1+y*5=350
solving the above equation we get,x=50 - 9 years agoHelpfull: Yes(0) No(0)
- let no of 5 rs coin be x and no of 1 rs coin be y . Then 5x + 1y = 350 and x+y =110
x = 60 and y = 50.
therefore answer is 50 ruppes 1 coin .
- 9 years agoHelpfull: Yes(0) No(0)
- no of 5rs coin=60
no of 1rs coin=50
- 9 years agoHelpfull: Yes(0) No(0)
- x+5y=350
x+y=110
x=50 - 9 years agoHelpfull: Yes(0) No(0)
- let no of coins of re.1=x.
then, 1*x + 5*(110-x)=350
x=50 - 9 years agoHelpfull: Yes(0) No(0)
TCS Other Question
A fortune teller has a unique way of predicting his customer’s prognosis. He has three parrots kept in three different cages. Each cage has three cards with a one digit non-zero number inscribed on every card. No two cards have the same number and no cage contains two cards with the number totaling ten. Further the total of numbers on the three cards in the first cage is greater by two than that in the second and by four than that in the third. When a customer asks for his prognosis, the fortune teller lets out the three parrots, which randomly pick one card out of their respective cages. Before the prognosis is made, the fortune teller totals the numbers on the three cards picked out by the parrots and charges the customer the same number of rupees as the total of the numbers on the cards. One day a customer paid seven rupees for his prognosis.
Which of the following combinations of cards may be picked for prognosis?
(a) 5, 7, 8
(b) 7, 9, 4
(c) 2, 6, 3
(d) 1. 3, 8
(e) None of these
a cow and a horse are bought for rs 200000