2nd nov 2014 cryptography

______V I A
______G O T
--------------
____G R O T
__A A R O *
A I A G * *
--------------
A S T A R T

• ______5 7 1
  ______3 2 6
  ------------------
  ____3 4 2 6
  __1 1 4 2 *
  1 7 1 3 * *
  -------------------
  1 8 6 1 4 6
• 10 years agoHelpfull: Yes(13) No(2)
• Hint
  
  A*T=T
  A*O=O
  A*G=G
  this can only be possible when A=1.now
  VIA*O=AARO. u can easily solve this problem
• 10 years agoHelpfull: Yes(9) No(3)
• is there any book for solving cryptography question ? i am going to write elitmus exam so please refer any book or link in my mail id "kingrakesh0467@gmail.com" . your response will be highly appriceated.
• 10 years agoHelpfull: Yes(8) No(0)
• A*T=T
  A*O=O
  A*G=G
  this can only be possible when A=1
  put a = 1 then first assume the value of O which cannot be 0,1 so take it 2 THIS WILL LOOK LIKE
  
  V I 1
  G O T
  --------------
  G R O T
  1 1 R O *
  1 I 1 G * *
  --------------
  1 S T 1 R T
  
  NOW ASSUME THE VALUE OF O FIRST RATHER THAN T OR G IT WILL HELP WHILE SOLVE U
  SO O CANNOT BE 0 OR 1 SO TAKE IT AS 2 AND REPLACE IN THE Q
  
  V I 1
  G 2 T
  --------------
  G R 2 T
  1 1 R 2 *
  1 I 1 G * *
  --------------
  1 S T 1 R T
  SINCE T CANNOT BE MORE THAN 9 SO THERE IS NO CARRY HENCE R WILL DEFINATELY BE 4 REPLACE IT
  
  V I 1
  G 2 T
  --------------
  G 4 2 T
  1 1 4 2 *
  1 I 1 G * *
  --------------
  1 S T 1 4 T
  
  SINCE THERE IS NO CARRY FROM 2+2 S0 4+4+G =1 ONLY WHEN G IS 3 REPLACE IN Q
  
  V I 1
  3 2 T
  --------------
  3 4 2 T
  1 1 4 2 *
  1 I 1 3 * *
  --------------
  1 S T 1 4 T
  
  SINCE 4+4+3 IS GIVING A CARRY SO T MUST BE 6
  HENCE REPLACE ALL VALUES
  V I 1
  3 2 6
  --------------
  3 4 2 6
  1 1 4 2 *
  1 I 1 3 * *
  --------------
  1 S 6 1 4 6
  NOW REST U CAN SOLVE AS V I T *6 = 3 4 2 6 WHICH MEANS V I MUST BE 5,7 RESPECTIVELY
  
  HENCE FURTHER SOLVING THIS IT WILL LOOK LIKE THIS
  
  5 7 1
  3 2 6
  --------------
  3 4 2 6
  1 1 4 2 *
  1 7 1 3 * *
  --------------
  1 S 6 1 4 6
  
  HAVE U GOT IT
  
  
• 10 years agoHelpfull: Yes(8) No(2)
• how to solve easily ? pls tell me
  
• 10 years agoHelpfull: Yes(2) No(0)
• guys before starting crypt problems u have to remember some key points.
  1. no two alphabets have same number.
  2. number values lie between 0 to 9.
  
  now looking at the problem .
  VIA*T = GROT.
  VIA*O = AARO.
  VIA*G = AIAG.
  Now basic maths.
  1*2=2.
  1*3=3.
  1*4=4.
  f.ex VIA*T=GROT.
  this can be only possible when A=1.
  now we have value of A.
  we can proceed further.
  now look at this .
  VIA*O=AARO.
  for simplicity write it as.
  A*O=O.
  CARRY+(I*O)=R.
  CARRY+(V*O)=AA.
  Now
  A=1. put value of O=2.
  carry=0.
  I*O=R.
  now focus on this.
  CARRY+V*O=AA.
  _______+V*2=11.
  this can only be possible when
  v=5. and the carry generated I*O=R. is 1.
  1+5*2=11
  v=5,O=2,A=1.
  now
  I*O=R.
  7*2=14. R=4. carry=1.
  now er have
  A=1
  O=2.
  I=7.
  R=4.
  V=5.
  now we can solve it easily
  
  571
  326
  _____________________
  3426
  1142
  1713
  __________________
  186146
  .
  guys i know its a little bit complicated. u can learn crypt only by practise.
  if anyone had problem contact on me.
  I am willing to help anyone .
  Wish u happy learning.
  https://www.facebook.com/virgo7101
• 10 years agoHelpfull: Yes(2) No(0)
• 5 7 1
  3 2 6
  ----------------------
  3 4 2 6
  1 1 4 2 *
  1 7 1 3 * *
  -----------------------------
  1 8 6 1 4 6
• 10 years agoHelpfull: Yes(1) No(0)
• ______V I A
  ______G O T
  --------------
  ____G R O T
  __A A R O *
  A I A G * *
  --------------
  A S T A R T
  
  T*A = T
  O*A = O
  G*A= G
  
  ==> A MUST BE 1
  REPLACE A WITH 1
  
  ______V I 1
  ______G O T
  --------------
  ____G R O T
  __1 1 R O *
  1 I 1 G * *
  --------------
  1 S T 1 R T
  
  OBSERVE MULTIPLES OF
  V I A * O = A A R O
  REPLACE IT WITH
  V I 1 * O = 1 1 R O
  THIS CASE SATISFY ONLY WHEN O*? = GREATER THAN 10
  ==> 5 I 1 * 2 = 10 ? 2
  BUT WE WANT 11 IN PLACE OF 10 SO CHECK FOR VALUE OF I
  5 6 1 * 2 = 1 1 2 2
  THIS IS NOT SATISFY THE CONDITION BECAUSE I != O
  LETS TRY WITH 5 7 1 * 2 = 1 1 4 2
  
  SO WE GOT THE VALUES V=5, I=7, R=4 & O=2
  
  REPLACE THE GIVEN PUZZLE WITH THEIR VALUES
  
  
  ______5 7 1
  ______G 2 T
  --------------
  ____G 4 2 T
  __1 1 4 2 *
  1 7 1 G * *
  --------------
  1 S T 1 4 T
  
  SIMILARLY CONSIDER 3RD MULTIPLIERS
  
  5 7 1 * G = 1 7 1 G
  
  BY TRIAL AND ERROR METHOD WE GET G=3
  
  5 7 1 * 3 = 1 7 1 3
  
  REPLACE THE PUZZLE WITH THEIR VALUES
  
  ______5 7 1
  ______3 2 T
  --------------
  ____3 4 2 T
  __1 1 4 2 *
  1 7 1 3 * *
  --------------
  1 S T 1 4 T
  
  SIMILARLY CONSIDER 1ST MULTIPLIER
  
  5 7 1 * T = 3 4 2 T
  
  BY TRIAL AND ERROR METHOD WE GET T=6
  
  REPLACE THE PUZZLE WITH THEIR VALUES
  
  ______5 7 1
  ______3 2 6
  --------------
  ____3 4 2 6
  __1 1 4 2 *
  1 7 1 3 * *
  --------------
  1 S 6 1 4 6
  
  SO FINALLY 1+7 = 8=S
  
  SO THE VALUES OF THIS CRYPTARITHAMATIC PUZZLE IS...
  
  V=5, I=7, A=1, G=3, O=2, T=6, R=4, & S=8.
  
  
  tHANL
• 10 years agoHelpfull: Yes(1) No(0)
• 571
  *326
  .....................
  3426
  1142
  1713
  .......................
  18646
  
• 10 years agoHelpfull: Yes(1) No(0)
• 571*326=186146
• 10 years agoHelpfull: Yes(0) No(0)
• Atul please help me to solve this......I m new in crypt.
  VIA*O=AARO
• 10 years agoHelpfull: Yes(0) No(0)
• sumit yr mera aaj 9 nov ko exam hai. evening me detail me bataunga :)
• 10 years agoHelpfull: Yes(0) No(0)
• can u please explain the problem solution completely
• 10 years agoHelpfull: Yes(0) No(0)
• 571
  * 326
  -------------
  3426
  + 1 142 *
  + 1713 **
  ------------------
  186146
• 10 years agoHelpfull: Yes(0) No(0)
• A=1
  O=2
  V=5
  R=4
  I=7
  G=3
  S=8
  T=6
  
  571
  *326
  --------------------
  4326
  1142
  1713
  ----------------
  186146
  ----------------
• 10 years agoHelpfull: Yes(0) No(0)