12 labours construct 120 toys in 8 days working 8 hours per day If two of them leave the work

less labours more days=>10:12
more toys more days => 120:120 ::8:x (no. of days let say x are required)
less hours more days => 6:8

solving this we get
x=12*120*64/120*10*6
so we get x=12.8 days.
10 years agoHelpfull: Yes(7) No(2)
solving by man-days concept
12*8*8=10*6*days
days=12.8
therefore 13 days are required to finish te job.
10 years agoHelpfull: Yes(2) No(1)
[here 2 labours leave so we take 10 labours,and 120 toys are same both case so not to need to take 120 toys in problem]
12 labours-8hrs work=8 days
1 labours- 1hrs work=8*8*12 days
1 labours-6 hrs work=(8*8*12)/6 days
10 labours-6hrs work=(8*8*12)/(6*10)days=12.8 days
9 years agoHelpfull: Yes(2) No(0)
labour 12 :10

hrs 8:6

less labour =>more days
less hours=>more days..indirect propotional

12*8*8=x*6*10
x=12.8
9 years agoHelpfull: Yes(1) No(0)
labours toys days hours total workng hours
1 2 120 8 8 64
10 120 x 6 6x

here toys are same
less labour, more working hours (indirect proportion)
10:12 =64:6x
6x=12*64/10 =>x=76.8/6==12.8
9 years agoHelpfull: Yes(1) No(0)
w1/(m1d1h1)=w2/(m2d2h2)
w1=w2
m1d1h1=m2d2h2
12*120*8=10*d2*6
d2=192
10 years agoHelpfull: Yes(0) No(13)
12*8*6=10*8*x

7 1/2
9 years agoHelpfull: Yes(0) No(3)
12*8*64=10*x*6
x=102.4
103 days
9 years agoHelpfull: Yes(0) No(4)
use chain rule
9 years agoHelpfull: Yes(0) No(1)

12 labours construct 120 toys in 8 days working 8 hours per day. If two of them leave the work, then how many days are required to do the same work with a working of 6 hours per day.