12 labours construct 120 toys in 8 days working 8 hours per day. If two of them leave the work, then how many days are required to do the same work with a working of 6 hours per day.

• w1=w2
  m1d1h1=m2d2h2
  12*8*8= 10*d2*6
  d2=12.8 days
• 9 years agoHelpfull: Yes(43) No(1)
• less labours more days=>10:12
  more toys more days => 120:120 ::8:x (no. of days let say x are required)
  less hours more days => 6:8
  
  solving this we get
  x=12*120*64/120*10*6
  so we get x=12.8 days.
• 9 years agoHelpfull: Yes(7) No(2)
• solving by man-days concept
  12*8*8=10*6*days
  days=12.8
  therefore 13 days are required to finish te job.
• 9 years agoHelpfull: Yes(2) No(1)
• [here 2 labours leave so we take 10 labours,and 120 toys are same both case so not to need to take 120 toys in problem]
  12 labours-8hrs work=8 days
  1 labours- 1hrs work=8*8*12 days
  1 labours-6 hrs work=(8*8*12)/6 days
  10 labours-6hrs work=(8*8*12)/(6*10)days=12.8 days
• 9 years agoHelpfull: Yes(2) No(0)
• labour 12 :10
  
  hrs 8:6
  
  less labour =>more days
  less hours=>more days..indirect propotional
  
  12*8*8=x*6*10
  x=12.8
  
• 9 years agoHelpfull: Yes(1) No(0)
• labours toys days hours total workng hours
  1 2 120 8 8 64
  10 120 x 6 6x
  
  here toys are same
  less labour, more working hours (indirect proportion)
  10:12 =64:6x
  6x=12*64/10 =>x=76.8/6==12.8
  
• 9 years agoHelpfull: Yes(1) No(0)
• w1/(m1d1h1)=w2/(m2d2h2)
  w1=w2
  m1d1h1=m2d2h2
  12*120*8=10*d2*6
  d2=192
  
• 9 years agoHelpfull: Yes(0) No(13)
• 12*8*6=10*8*x
  
  7 1/2
• 9 years agoHelpfull: Yes(0) No(3)
• 12*8*64=10*x*6
  x=102.4
  103 days
• 9 years agoHelpfull: Yes(0) No(4)
• use chain rule
  
• 9 years agoHelpfull: Yes(0) No(1)