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M men agree to purchase a gift for Rs. D. If three men drop out how much more will each have to contribute towards the purchase of the gift ?
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- initially, each contributION = D/M
after, 3 men droped, each contribution = D/(M-3)
reqd more amount = D/(M-3) - D/M = D[1/(M-3) - 1/M] = 3D/M(M-3)
- 10 years agoHelpfull: Yes(26) No(1)
- according to the question.....
M men agree to puchase a gift for D
therefore for d the gift has to be purchased
so each contributed=D/M
THEN 3 men dropped out from M=D/M-3
REQUIRED CONTRIBUTION FOR THE GIFT=D/(M-3) - D/M = D[1/(M-3) - 1/M]
= 3D/M(M-3) ANSWER.....
- 10 years agoHelpfull: Yes(2) No(2)
- initial contribution = D/M
final contribution = D/(M-3)
Difference = D/(M-3) - D/M
=>Difference =D[{M - (M-3)}/{M X (M-3)}]
=>Difference= 3D/[M(M-3)] - 10 years agoHelpfull: Yes(2) No(1)
- M contribute for gift worth= D
each share in it= D/M
when 3 dropped then
each share increases = D/ (M-3)
extra share given by them = D/ (M-3) - D/M = 3D/M(M-3) - 10 years agoHelpfull: Yes(1) No(0)
- M men purchased gift of M
so, contribution of each man=D/M
now 3 men reduces, so the contribution of each men inc by 3D/M among (M-3) men
i.e M-3=3D/M
1M=3D/M(M-3)
total contribution of each man= D/M+3D/M(M-3)
=D/(M-3) - 10 years agoHelpfull: Yes(1) No(0)
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