IBM
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Numerical Ability
Time and Work
A can do work in 6 day and B can do in 8 and C can do in 12 days but b left after working for 6 days for how many no of day A and C shluld work
Read Solution (Total 4)
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- B worked for 6 days completing 6/8th of the work i.e. 3/4th of work
B's one day work is 1/8 so in 6 days he completes 6/8th of the work).
Now A and C come in together to complete whatever remains.
Their one day's combined work is (1/6 + 1/12 )= 1/4 (which is equal to the remaining work).
Hence A and C complete the work in 1 day. - 11 years agoHelpfull: Yes(24) No(2)
- One day work of A B C is 1/6 1/8 1/12
one day work of all A+B+C is 1/6+1/8+1/12 = 9/24 = 3/8
6 day ABC work together 3/8 * 6 = 9/4
remaining work 9/4-1=5/4
A+C can do one day work 1/4
4*5/4=5days
Answer 5 days
- 12 years agoHelpfull: Yes(6) No(27)
- b worked= 6/8 days=3/4days
remaining work=1-3/4=1/4
A and C work together = 1/6 + 1/12=1/4
which is same as remaining work
so,A and C complete thw work in 1 days - 9 years agoHelpfull: Yes(5) No(0)
- Answer 1 day.
In 6 day
B work 6/8= 3/4 part of work
then remaining work is
1-3/4 =1/4 part
A +C work ( 1/6+ 1/12)part= 1/4 part of 1 day
so remaining work done by in 1 day - 9 years agoHelpfull: Yes(2) No(0)
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