4 thieves entere a bakery and stoled bread one after the other.Each one took half of the total number of breads+half a loaf.If 3 breads were remaining what is the total number of breads.

• half of bread and half of loaf of a bread
  for four half no. of subsequent bread and half loaf is
  (x2 +1/2) +(x4 +1/2) + (x8+1/2) + (x16 +1/2) + 3=x
  15x/16 +5=x
  x/16=5
  x=80
  its the answer
• 9 years agoHelpfull: Yes(27) No(8)
• Let total number of breads available is x.
  Then x/2+x/4+x/8+x/16+3=x
  By solving this we can get x=48.
  
• 12 years agoHelpfull: Yes(15) No(28)
• let the total no of breads are X
  now,each one took half of bread and half a loaf so
  1st one=X/2
  2nd one took half i.e from rest means= X/4
  similarly 3rd = X/8
  4th=X/16
  and all took half a loaf i.e =1/2*4
  and in question they mentioned 3 breads are remains
  total (X)=(X/2+X/4+X/8+X/16)+1/2*4+3
  X=15/16x+2+3
  X/16=5
  so x= 16*5
  =80
• 7 years agoHelpfull: Yes(4) No(1)
• Let total number of breads available is x.
  Then x/2+x/4+x/8+x/16+2(=4*1/2 since each person take half of a loaf)+3=x
  By solving this we can get x=80.
  
• 9 years agoHelpfull: Yes(2) No(2)
• it will be 63
  procedure:
  let initially der are x breads
  1st thief takes=x/2 +1/2 ,so remaining=x-(x/2+1/2)=x/2-1/2
  2nd thief takes=1/2+1/2*(x/2-1/2)=1/2+x/4-1/4=x/4+1/4 so remain=x/2-1/2-x/4-1/4=x/4-3/4
  3rd thief takes=1/2 +1/2*(x/4-3/4)=1/2+x/8-3/8=x/8+1/8 so remain=x/4-3/4-x/8-1/8=x/8-7/8
  4th thief takes=1/2+1/2*(x/8-7/8)=1/2+x/16-7/16=x/16+1/16 so remain=x/8-7/8-x/16-1/16=x/16-15/16
  so x/16-15/16=3
  x=48+15=63(ans)
• 7 years agoHelpfull: Yes(2) No(0)
• give the poper ans
  
  
• 9 years agoHelpfull: Yes(1) No(4)
• remaining 3 =so before that it will be 6 last thieve takes 3 thats why we get remaining 3 .get back to 3 thieve=12 2thieve=24 1st thieve=48 so total number of bread is 48
• 9 years agoHelpfull: Yes(1) No(2)
• (x/2+x/4+x/8+x/16)+0.5*4+3=x
  15x/16+5=x
  x/16=5
  x=80 (Ans)
• 8 years agoHelpfull: Yes(1) No(2)
• please explain correct solution
• 9 years agoHelpfull: Yes(0) No(0)