We went to some place and it rained for 15 days. Clear mornings are followed by rainy afternoons. And all clear afternoons are preceeded by rainy mornings. It rained continuiosly for 10 mornings. It rained for 12 afternoons. And 13 days are without any rain. How many days we stayed in the new place?

• It rained continuously for 10 days
  so out of 12 noon , already 10 noons are covered...
  so 10days + 2noons =12 days
  
  ans=12(rainy)+ 13(without rain) = 25
  
  u can correct me if i am wrong :)
• 11 years agoHelpfull: Yes(3) No(2)
• guys refer this example and solve this question in same way
  
  http://www.braingle.com/palm/teaser.php?op=2&id=10172&comm=1
  A group of workers from the Madadian Kebab Recycling Factory went on a holiday to the sun soaked coast of Madadia. It rained for 13 days. But when it rained in the morning, the afternoon was lovely. And when it rained in the afternoon, the day was preceded by clear morning.
  
  Altogether there were 11 very nice mornings and 12 very nice afternoons. How many days did their holiday last?
  
  
  Answer:
  The holiday lasted for 18 days.
  
  Let's assume the number of days as follows:
  Rain in the morning and lovely afternoon = X days
  Clear morning and rain in the afternoon = Y days
  No rain in the morning and in the afternoon = Z days
  
  Number of days with rain = X + Y = 13 days
  Number of days with clear mornings = Y + Z = 11 days
  Number of days with clear afternoons = X + Z = 12 days
  
  Solving above 3 equations, we get X = 7, Y = 6 and Z = 5
  
  Hence, total number of days on holiday = 18 days
  
  
  
  now this ques to be solved in the same way
  
  We went to some place and it rained for 15 days. Clear mornings are followed by rainy afternoons. And all clear afternoons are preceeded by rainy mornings. It rained continuiosly for 10 mornings. It rained for 12 afternoons. And 13 days are without any rain. How many days we stayed in the new place?
  Let's assume the number of days as follows:
  Rain in the morning and lovely afternoon = X days
  Clear morning and rain in the afternoon = Y days
  No rain in the morning and in the afternoon = Z days
  
  Number of days with rain = X + Y = 15 days ->1eqn
  Number of days with clear mornings = Y + Z = 12 days-> 2eqn
  Number of days with clear afternoons = X + Z = 10 days ->3eqn
  Solve eqn 1& 2 we get x – z = 5 ->4 eqn
  Solve eqn 3 & 4 we get x = 13
  Substitute x=13 in eqn 1 we get y=2
  Substitute y=2 in eqn 2 we get z=10
  Hence, total number of days on holiday = x+y+z days.= 13+2+10 =25 days (ans)
• 7 years agoHelpfull: Yes(2) No(0)
• Ans: 25
  Exp:
  It rained for 12 afternoons. And 13 days are without any rain.
  So, there r 12+13=25 days stayed in the new place
• 11 years agoHelpfull: Yes(1) No(3)
• please can any one give clear explanation for this question
• 7 years agoHelpfull: Yes(1) No(0)