If a salesman s average is a new order every other week, he will break the office record of the year. However, after 28 weeks, he is six orders behindschedule. In what proportion of the remaining weeks does he have to obtain a new order to break the record?

• in the remaining 24 weeks(i.e, 52-28), he has to complete the 6 orders plus 12 orders(**) which were the only ones supposed to be completed in the remaining 24 weeks.so his orders per week become 6/24 + 12/24 = 3/4 ans.
  **(in 52 weeks he must get 26 orders in 28 weeks S is to cover 14 order,therefore 12 orders remains for the next 24 weeks.)
• 10 years agoHelpfull: Yes(3) No(2)
• Assume there are 52 weeks in one year.
  Since he supposed to have a new order for every two weeks, he
  needs 52/2 = 26 orders to break the office record.
  
  Now after 28 weeks,he has got only 28/2 -6 = 8 orders.
  Hence,he needs 26-8 = 18 new orders in the remaining 24= 52-28 weeks to break the office record.
  
  Compute 24 orders/18 weeks = 4/3 orders/week ,
  we see that averagely he has a new order for
  every 4/3 weeks in the remaining weeks to break the office record.
• 8 years agoHelpfull: Yes(2) No(1)
• http://www.algebra.com/algebra/homework/word/finance/Money_Word_Problems.faq.question.2109.html
• 9 years agoHelpfull: Yes(1) No(0)