If the radius of the circle is decreased by 50% then the area will be reduced by what percentage.

• Let the radius of the circle is :2x
  then Area of the circle:pie*4x^2
  New radius after decrease by 50%:x
  Area now is:pie*x^2
  Area reduced by pie3x^2
  %age reduction: (3pie x^2/pie 4x^2)*100=75%
• 13 years agoHelpfull: Yes(6) No(0)
• it will be 75% if radius is reduced by 50% then it means that radius is now half of the previous radius. Therefore the area will be 1/4 of the actual radius and so the area is reduced by 75%
• 10 years agoHelpfull: Yes(4) No(0)
• If the radius is increased by 50% then it is 1.5 and the circumference=3pi
  3pi/2pi=3/2, an increase of 50%
• 9 years agoHelpfull: Yes(1) No(0)
• if 50% reduced, new radius = 50/100 * R = R/2
  new area= pi* (1/2*R)^2 = pi * R^2 / 4
  area= old area - new area => ( pi * R^2) - (pi * R^2 / 4) = 3 * pi *R^2 / 4
  so, ( 3 * pi *R^2 / 4) * (1/ pi * R^2) *100 = 75%
• 8 years agoHelpfull: Yes(0) No(0)