rectangular room has width twice of its length. When 6 is decreased from both length and width then its area is differed by 108 so find the width.

• Let the length be x, Then width will be 2x
  The area : 2x^2
  After decrease: Length(x-6) & Width(2x-6)
  Now, the area:x^2-9x+18
  Hence, the eq. is 2x^2-(2x^2+18x+36)=108
  Solving, we get x=8, width is 16
• 13 years agoHelpfull: Yes(5) No(7)
• Area of rectangle: length x width
  =L*W =L*2L= 2(L^2)
  when 6 is decreased, the length= (L-6), width=(2L-6)
  area= (L-6)(2L-6) = 2(L^2)-18L+36
  area difference=108
  therefore, 18L-36=108
  18L=144, or, L=8. width=2*8=16
• 10 years agoHelpfull: Yes(1) No(0)
• let the length be a then the width will be 2a
  then the area=a*2a=2(a^2)
  after dec. of length and width
  new length=(a-6)
  new width=(2a-6)
  so area=(a-6)*(2a-6)=2a^2-18a+36
  now the difference=>2a^2-(2a^2-18a+36)=108
  =>18a-36=108
  =>18a=108+36=144
  =>a=144/18=8
  so width=2a=8*2=16
• 10 years agoHelpfull: Yes(0) No(0)