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Numerical Ability
Permutation and Combination
In a party 10 ate fruits, 15 ate cereals and 8 both. What is the number of people who ate at least one?
Read Solution (Total 4)
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- In a party 10 ate fruits, 15 ate cereals & 8 both.
So total no of person=10+15-8=17
8 person ate both,
Then a people who ate least one=17-8=9 Ans - 11 years agoHelpfull: Yes(21) No(6)
- 10+15-8=17
- 7 years agoHelpfull: Yes(5) No(1)
- 10-8=2
15-8=7
so 7+2=9
:) - 8 years agoHelpfull: Yes(3) No(2)
- 10 ate fruit. 15 ate cereal and 8 both
Therefore:
2 ate Fruit ONLY
7 ate Cereal ONLY
8 ate both.
People who had ATLEAST ONE is NOT the same as people who had ONLY ONE:
2+7=9 People had ONLY ONE
7+8+2=17 People had ATLEAST ONE - 6 years agoHelpfull: Yes(0) No(0)
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