Every day a cyclist meets a train at a particular crossing. The road is straight before the crossing and both are traveling in the same direction. Cyclist travels with a speed of 10 Kmph. One day the cyclist comes late by 25 min. and meets the train 5km before the crossing. What is the speed of the train.

• when the cyclist meets the train: he has 5 km to go, so for the cyclist 30 min to go to crossing.
  The moment that train passes crossing devides this 30 min. in two parts:
  second part: t=25 min (since the cyclist will pass the crossing 25 min later),
  
  first part: t=30-25= 5 min, In this 5 minutes the train has travelled 5 km. So the speed should have been 60 km/h
  
  This of course only yields if you disregard the length of the train....
• 9 years agoHelpfull: Yes(14) No(1)
• 60 Kmph
• 14 years agoHelpfull: Yes(5) No(10)
• Cyclist and Train meet at 5 km point.
  If cyclist had left on time, they would be 25 min at 10km/h further --->10km/h * 25/60 h = 25/6 km
  This leaves the cyclist 5/6 km from the cross road, when the train is at 5 km
  Time cyclist takes to travel this 5/6 km = distance / speed
  (5/6) / 10 = 1 / 12 hours
  The train travels 5 km in 1/12 h
  speed = distance / time
  5 / (1/12) = 5 * 12 = 60 km / h
• 8 years agoHelpfull: Yes(1) No(3)