There are N coins on a table. There are two players A&B. You can take 1 or 2 coins at a time. The person who takes the last coin is the loser. A always starts first

1. If N=7
a) A can always win by taking two coins in his first chance
b) B can win only if A takes two coins in his first chance.
c) B can always win by proper play
d) none of the above

2. A can win by proper play if N is equal to
a) 13
b) 37
c) 22
d) 34
e) 48

3. B can win by proper play if N is equal to
a) 25
b) 26
c) 32
d) 41
e) none

4. if N<4, can A win by proper play always

• yes... if A leaves odd number of coins to B all the time, then A is the winner.
• 14 years agoHelpfull: Yes(0) No(6)
• 1. c
  because whether A takes 1 or 0, B has to make sum of A+ his ,so that 1 is always left for A.
  2.e
  A can win by proper play when N is a multiple of 3
  3. e)
  b can always win by proper play by making sum of takes of A and himself=3.
  4.For n=2,it doesn't hold.
• 11 years agoHelpfull: Yes(0) No(2)