A game is played between 2 players and one player is declared as winner. All the winners from first round are played in second round. All the winners from second round are played in third round and so on. If 8 rounds are played to declare only one player as winner, how many players are played in first round?

• 2^8=256 teams
• 14 years agoHelpfull: Yes(47) No(8)
• 2^8=256
• 14 years agoHelpfull: Yes(15) No(3)
• 2^8=256 players
• 12 years agoHelpfull: Yes(14) No(3)
• by having 256 players in first round,the next round would be having 128 players and so on....
  finally after 8 rounds we get 1 player as winner
• 10 years agoHelpfull: Yes(3) No(5)
• khubkmjuhjh
• 9 years agoHelpfull: Yes(3) No(4)
• 2^7=128 teams
• 7 years agoHelpfull: Yes(0) No(3)
• it is said that among 2 players only one is selected as winner.
  At the 8th round one player is declared as winner. Which means that there were 2 players playing at the 8th round.
  In order to get 2 players ath the 8th round there must be 4 players at the 7th round so that 2 are selected to the 8th round.
  Hence, there are
  8 players at 6th round
  16 players at 5th round
  32 players at 4th round
  64 players at 3rd round
  128 players at 2nd round
  256 players at 1st round
  
  Hence the answer is 256
• 5 years agoHelpfull: Yes(0) No(0)
• ans is 2^7
• 4 years agoHelpfull: Yes(0) No(0)