Peter and paul are 2 friends.Sum of their ages is 35 years.Peter is twice as old as paul was when peter was as old as paul is now.What is the present age of peter?

• suppose peter age=h
  paul age=k
  h+k=35 (given)
  now suppose t years ago h was twice k.
  (h-t)=2(k-t).....1
  at that time h was as old as paul now
  h-t=k........2
  so from 1 & 2
  2k-2t=k;
  k=2t.......3
  from 2 & 3
  h=3t;......4
  from 1 5t=35;
  t=7;
  from 4 h=21....
  so peter is 21 year old...this should be ans.
• 12 years agoHelpfull: Yes(13) No(5)
• present age of 2 friends is 35 years.
  peter paul
  2x y = 35
  y x = 35 - 2(2x-y)
  solving this x=20 and y =15
  so peter current age is 20
  ans is 20.
  
• 14 years agoHelpfull: Yes(10) No(5)
• present peter age is 20
  present age of 2 friends is 35 years.
  
  2x+y = 35
  y+x = 35 - 2(2x-y)
  solving this x=20 and y =15
  so peter current age is 20
  ans is 20.
• 14 years agoHelpfull: Yes(5) No(0)
• Present age of Peter is 21.
  Solution : Present age of Peter = 21. Present age of Paul = 14. Sum = 35.
  When Peter was as old as Paul is now, i.e 14, Paul was 7. So Peter was twice old as Paul that time.
• 14 years agoHelpfull: Yes(4) No(5)
• 
  >>The sum of their ages is 35 years.>Peter is twice as old as Paul was when Peter was as old as Paul is now.
• 9 years agoHelpfull: Yes(0) No(0)
• Age of Peter is 21.
  As in the given question
  Lets Peter age =x
  and paul age 35-x;
  and when peter was as old as paul is now mean when peter is 35-x yr old
  then it is 2*(35-x-k)
  so let wer equate these
  35-x=2*(35-x-k)
  x+2k=35
  x-k=2k
  x=3k
  and get
  k=7
  and then x=21
• 6 years agoHelpfull: Yes(0) No(0)