Out of 7 children the youngest is boy then find the probability that all the remaining children are boys
a) 1/64
b) 1/32
c) 1/128
d) 1/256

• a) 1/64 ....
  the probability of the remainin children bein boys will be(1/2*1/2*1/2*1/2*1/2*1/2)=1/64
  1/2 comes becos each of child could either be a boy or a gal ...so probaility vl be 1/2....
• 13 years agoHelpfull: Yes(164) No(8)
• probability of a boy child is 1/2
  therefore -> (1/2)*(1/2)*(1/2)*(1/2)*(1/2)*(1/2) =1/64
• 13 years agoHelpfull: Yes(36) No(1)
• there is only one possible whether boy or girl. here we needs 6 boys so (1/2*1/2*1/2*1/2*1/2*1/2)=1/64.
  ans a)1/64
• 13 years agoHelpfull: Yes(33) No(1)
• as the prob of a boy = 1/2
  no of remaining child = 7-1
  there fore req prob = (1/2)^6=1/64
• 12 years agoHelpfull: Yes(16) No(0)
• 1/64 since 1/(2^6)=1/64
• 13 years agoHelpfull: Yes(14) No(3)
• 1/2^6=1/64
• 13 years agoHelpfull: Yes(14) No(4)
• 1/64
• 13 years agoHelpfull: Yes(10) No(5)
• (1/2)^6
  
  (1/2*1/2*1/2*1/2*1/2*1/2)=1/64
  
• 10 years agoHelpfull: Yes(1) No(0)
• out of 7 ,1 is already boy then remaining are 6.
  and the probability of boy is =1/2
  so solution is =1/2*1/2*1/2*1/2*1/2*1/2=1/64
• 8 years agoHelpfull: Yes(1) No(0)
• they ask you to find only remaining 6 are the boys.
  the probability of the boy is 1/2.
  so probability of 6 boys are 1/2*1/2*1/2*1/2*1/2*1/2=1/64.
• 9 years agoHelpfull: Yes(0) No(0)
• ...........
• 7 years agoHelpfull: Yes(0) No(0)
• (1/2)^6 =1/64
• 4 years agoHelpfull: Yes(0) No(0)