GENPACT Company Numerical Ability Pipes and Cistern

A tap can fill a tank in 6 hours. After half the tank is filled, three more similar taps are opened. What is the total time taken to fill the tank completely ?
A. 3 hrs 15 min
B. 3 hrs 45 min
C. 4 hrs
D. 4 hrs 15 min

Read Solution (Total 1)

time taken by one tank to fill half the tank=4*(1/6)

Part filled by the four taps in 1 hour=4*(1/6)
remaining part=1/2
therefore 2/3:1/2::1:x
x=3/4hr=(3/4)*60=45min
total time =3 hr 45 min
12 years agoHelpfull: Yes(3) No(2)

GENPACT Other Question

A large tanker can be filled by two pipes A and B in 60 minutes and 40 minutes respectively. How many minutes will it take to fill the tanker from empty state if B is used for half the time and A and B fill it together for the other half ?
A. 15 min
B. 20 min
C. 27.5 min
D. 30 min Two pipes A and B can fill a tank in 6 hours and 4 hours respectively. If they are opened on alternate hours and if pipe A is opened first, in how many hours, the tank shall be full ?
A. 4 hrs
B. 5 hrs
C. 7 hrs
D. 9 hrs