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Two pipes A and B can fill a tank in 6 hours and 4 hours respectively. If they are opened on alternate hours and if pipe A is opened first, in how many hours, the tank shall be full ?
A. 4 hrs
B. 5 hrs
C. 7 hrs
D. 9 hrs
Read Solution (Total 1)
-
- A's work in 1 hour = 1/6.
B's work in 1 hour = 1/4.
(A+B)'s 2 hour's work when opened alternately = (1/6 + 1/4)
= 5/12.
(A+B)'s 4 hour's work when opened alternately = 10/12
= 5/6.
Remaining part = (1 - 5/6)
= 1/6.
Therefore, total tank to fill the tank (4+1)hrs = 5 hrs. - 11 years agoHelpfull: Yes(5) No(2)
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