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How many 13 digit numbers are possible by using the digits 1,2,3,4,5 which are divisible by 4 if repetition of digits is allowed?
Read Solution (Total 7)
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- its 5^12
sol: the last two digits can be made in 5 different times(12,24,32,44,52)
and the first 11 digits can be made in
- - - - - - - - - - - - -
5 5 5 5 5 5 5 5 5 5 5 (5)
hence the total no of digits allowed are 5^12.
- 14 years agoHelpfull: Yes(20) No(3)
- Ans:244140625
If the number to be divisible by 4 then it must contains last two digits that must be divisible by 4. from given digits (1-5)only hence last digits to be 2 and 4 .
Hence possible last two digits will be 12,32,24,44,52
Remaining 11 places can be filled by (1-5) and it takes 5 ^11 possibilities
Hence total 5*5^11=244140625
- 14 years agoHelpfull: Yes(12) No(1)
- 5 power 12
- 14 years agoHelpfull: Yes(2) No(0)
- itz 5^12
- 14 years agoHelpfull: Yes(2) No(0)
- last two digits are 12,24,32,44,52.. totally 5
in 13 digit no, consider last two digit no as single digit..
from 1,2,3,4,5- create rest of 11..
ans s 5^12 - 14 years agoHelpfull: Yes(2) No(1)
- 5^12
- 14 years agoHelpfull: Yes(1) No(1)
- 5^12 is the answer
- 9 years agoHelpfull: Yes(0) No(0)
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