How many 13 digit numbers are possible by using the digits 1,2,3,4,5 which are divisible by 4 if repetition of digits is allowed?

• its 5^12
  
  sol: the last two digits can be made in 5 different times(12,24,32,44,52)
  
  and the first 11 digits can be made in
  - - - - - - - - - - - - -
  5 5 5 5 5 5 5 5 5 5 5 (5)
  hence the total no of digits allowed are 5^12.
  
• 13 years agoHelpfull: Yes(20) No(3)
• Ans:244140625
  If the number to be divisible by 4 then it must contains last two digits that must be divisible by 4. from given digits (1-5)only hence last digits to be 2 and 4 .
  Hence possible last two digits will be 12,32,24,44,52
  Remaining 11 places can be filled by (1-5) and it takes 5 ^11 possibilities
  Hence total 5*5^11=244140625
  
• 13 years agoHelpfull: Yes(12) No(1)
• 5 power 12
• 13 years agoHelpfull: Yes(2) No(0)
• itz 5^12
• 13 years agoHelpfull: Yes(2) No(0)
• last two digits are 12,24,32,44,52.. totally 5
  in 13 digit no, consider last two digit no as single digit..
  from 1,2,3,4,5- create rest of 11..
  ans s 5^12
• 13 years agoHelpfull: Yes(2) No(1)
• 5^12
• 13 years agoHelpfull: Yes(1) No(1)
• 5^12 is the answer
• 9 years agoHelpfull: Yes(0) No(0)