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There is a bacteria which has the probability of die 1/3 of its total number or it may tripled. Find out the probability
A. P=1/3+(2/3*p^3) B. P=2/3+(2/3*p^3) C. P=2/3+(1/3*p^3) D P=2/3+(2/3*p^3)
Read Solution (Total 3)
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- Option A is the answer
as probability of die is 1/3 which is not there in any of the options in the beginning - 13 years agoHelpfull: Yes(9) No(9)
- A is the answer... :)
- 9 years agoHelpfull: Yes(1) No(0)
- please give a strong reason for answer to be A.
how come A can be marked as a correct option.?? - 9 years agoHelpfull: Yes(1) No(0)
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