X and Y are brothers and they differ by 12 years. If 4 years ago, the age of X be twice the age of Y, find their present ages.
a.X = 28 yrs, Y = 16 yrs
b.X = 24 yrs, Y = 14 yrs
c.X = 20 yrs, Y = 8 yrs
d.X = 8 yrs, Y = 20 yrs

• ans is..a
  x-y=12............(1)
  x-4=2(y-4)............(2)
  solve it
  
• 11 years agoHelpfull: Yes(3) No(0)
• ans. 1st method-Diff in X and Y ages i.e (X-Y)=12yrs
  4yrs ago- (X=2Y),which means 'X' will be elder than 'Y'
  (X-4)=2(Y-4)
  On solving these equations ,we get
  X=28yrs while Y=16yrs
  2nd Method-
  Shortcut Hint -
  keep a glance over the options given
  option (B) and (D)cannot be possible as the difference b/w the ages of X and Y is 10yrs (24-14=10,which is nt possible as the difference should be of 12yrs)and -12yrs (8-20=-12yrs,which is nt possible as the difference should be of plus ie +12yrs ,as we are talking abt their ages and nt the past) resp. So, both these options are in any case nt possible. Similarly option (C)is also nt possible.
  Hence the answer is option (A)
• 10 years agoHelpfull: Yes(0) No(0)