Four years ago, the ratio of ages of Purple and Blue was 2:3, respectively. If the sum of their present ages is 28. Compute the ratio of their ages four years hence.
a.1:5
b.2:5
c.3:5
d.4:5

• let present age of purple be P
  Present age of blue be B
  so given P+B=28 -------- 1
  4 yrs ago
  ie p-4 / B-4 = 2/3 ----- 2
  solving eq 1 and eq 2
  we get
  p=12
  B=16
  4 yrs hence ratio of teir ages is
  (12+4)/(16+4)=4/5
  ans d
  
  
• 11 years agoHelpfull: Yes(10) No(1)
• (2x+4)+4/(3x+4)+4
  ==>2x+8/3x+16
  ==>given 2x+8+3x+16=28
  ==>5x+24=28
  ==>x:1=4:5
  ans d
• 11 years agoHelpfull: Yes(4) No(2)
• let (p-4)/(b-4)=2/3......>(a)
  also given p+b=28
  =>p=28-b.......>(1)
  put p= 28- b in (a)
  (28-b-4)/(b-4)=2/3
  by solving that we get
  72-3b=2b-8
  72+8=5b
  =>b=16
  then put bin (1)
  we get p value i.e p=12
  now required ratio is (p+4)/(b+4)
  =(12+4)/(16+4)
  =16/20
  =4/5
  Ans:4:5
  
  
• 11 years agoHelpfull: Yes(2) No(0)