A common foodstuff is found to contain .00125% iron. The serving size is 87.0 grams. If the recommended daily allowance is 18mg of iron, how many servings would a person have to eat to get 100% of the daily allowance of iron?

• in 87 gms 0.00125% contains iron = 125%* 87/100000 = 125/10^7 * 87
  to make it 18 mg of iron then 125*87/10^7 * X = 18* 10^(-3)
  x=16.55 = 17
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