The diagonal of a rectangle is sqrt(41) cm and its area is 20 sq. cm. The perimeter of the rectangle must be:
A. 9 cm B. 18 cm
C. 20 cm D. 41 cm

• diagonal of rectangle = sqrt(l^2 +b^2)=sqrt41
  area of rectangle = l*b=20
  then l=5,b=4
  we get perimeter of rectangle=2(l+b)=2(5+4)=18ans
  
• 9 years agoHelpfull: Yes(10) No(0)
• use pythagoras theorem answer is 18
• 9 years agoHelpfull: Yes(2) No(0)