A rectangular park 60 m long and 40 m wide has two concrete crossroads running in the middle of the park and rest of the park has been used as a lawn. If the area of the lawn is 2109 sq. m, then what is the width of the road?
A. 2.91 m B. 3 m
C. 5.82 m D. None of these

• Area of the park = (60 x 40) m2 = 2400 m2.
  
  Area of the lawn = 2109 m2.
  
  Area of the crossroads = (2400 - 2109) m2 = 291 m2.
  
  Let the width of the road be x metres. Then,
  
  60x + 40x - x2 = 291
  
  x2 - 100x + 291 = 0
  
  (x - 97)(x - 3) = 0
  
  x = 3.
• 9 years agoHelpfull: Yes(6) No(1)
• area of park=2400sq.m
  area of lawn=2109sq.m
  now area of crossroad=2400-2109=291sq.m
  now check using option, using option a i.e if width=2.91 and length=40(given) and sum this crossroad with another crossroad i.e width=2.91 and length=60(given)
  using above concept,
  2.91*40 + 2.91*60=291sq.m
  which matches the area of the crossroad as bove mentioned using(2400-2109)
• 9 years agoHelpfull: Yes(1) No(3)