IBM Company Numerical Ability Number System

If both 112 and 33 are factors of the number a * 43 * 62 * 1311, then what is the smallest possible value of 'a'?

Read Solution (Total 2)

a*43*62*1311 = a*43*2*31*19*23*3. 112=2^4*7 and 33= 3*11. to be a factor, the value of a must be 2^3*7*11 = 616.
11 years agoHelpfull: Yes(10) No(4)

It is wrong Question
Q is-->
If both 11^2 and 3^3 are factors of the number a * 4^3 * 6^2 * 13^11, then what is the smallest possible value of a?
Solution:answer is 363. How it is explain ....
10 years agoHelpfull: Yes(3) No(2)

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