IBM
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Numerical Ability
Number System
Anita had to do a multiplication. Instead of taking 35 as one of the multipliers, she took 53. As a result, the product went up by 540. What is the new product?
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- let the old product is x
so, (x/35)*53=x+540
this gives x=1050, this is the old product
The new product is 1050+540=1590 - 12 years agoHelpfull: Yes(13) No(1)
- 53x-35x=540
18x=540
x=30
the new prodct=53*30=1590 - 9 years agoHelpfull: Yes(9) No(0)
- x*35=y---1
x*53=(y+541)---2
solving both we get x=30 y=1050
new product=1051+540=1590
- 9 years agoHelpfull: Yes(1) No(0)
- http://questions.ascenteducation.com/iim_cat_mba_free_sample_questions_math_quant/number_theory/multiplication_number_theory_110803.shtml
- 9 years agoHelpfull: Yes(0) No(1)
- 35*x = y........eq1
53*x= y+540.....eq2
now put eqn1 in eqn23X = 35X+540
x=30
now 53*30=1590 - 4 years agoHelpfull: Yes(0) No(0)
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