IBM
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Numerical Ability
Number System
10^25 - 7 is divisible by
Read Solution (Total 2)
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- 10^25=10^1
10-7=3
hence it is divisible by 3..... - 12 years agoHelpfull: Yes(4) No(1)
- 3 since 9999999999999999999....3 3 divisibility rule
- 11 years agoHelpfull: Yes(1) No(0)
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