How many different factors are there for the number 48, excluding 1 and 48?

• 48=2^4*3^1
  Total No. of factors=5*2=10(each power of prime factor shall be increased by 1 and multiply)
  Exculding 1 and 48, the No. of factors would be 8
• 13 years agoHelpfull: Yes(7) No(1)
• To find the number of factors of a given number, express the number as a product of powers of prime numbers.
  
  In this case, 48 can be written as 16 * 3 = (24 * 3)
  
  Now, increment the power of each of the prime numbers by 1 and multiply the result.
  
  In this case it will be (4 + 1)*(1 + 1) = 5 * 2 = 10 (the power of 2 is 4 and the power of 3 is 1)
  
  Therefore, there will 10 factors including 1 and 48. Excluding, these two numbers, you will have 10 - 2 = 8 factors.
• 12 years agoHelpfull: Yes(2) No(2)
• 48 =2*2*2*2*3
  
  4 times 2 so 4+1=5
  1 time 3 so 1+1=2
  
  Number of factors of 48= 5*2=10
  Excluding 1 and 48
  10-2= 8 ( Ans )
• 8 years agoHelpfull: Yes(1) No(0)