IBM
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Numerical Ability
Permutation and Combination
How many words can be formed by re-arranging the letters of the word ASCENT such that A and T occupy the first and last position respectively?
Read Solution (Total 9)
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- A and T should occupy the first and last position, the first and last position can be filled in only one way. The remaining 4 positions can be filled in 4! Ways by the remaining words (S,C,E,N). hence by rearranging the letters of the word ASCENT we can form 1x4! = 4! words
- 13 years agoHelpfull: Yes(34) No(1)
- A and T are in the first and last position besides that we have 4 letters so 4!=24 number of words we can form..............,
- 13 years agoHelpfull: Yes(13) No(0)
- rearrange 4!-1=23 is ans
- 11 years agoHelpfull: Yes(3) No(2)
- 4!=24 is the number of ways
- 12 years agoHelpfull: Yes(2) No(0)
- 4!24 such combinations.
- 12 years agoHelpfull: Yes(2) No(4)
- 24 combinations...
- 12 years agoHelpfull: Yes(2) No(0)
- if the letters can be repeated then it can form 4 words excluding ascent.
- 13 years agoHelpfull: Yes(0) No(3)
- letters A and T have to occupy constants positions, so we should not considering them, then the letters S,C,E,N have to be arranged in the form of factorial i.e. 4!= 36
So the final answer is 36 - 12 years agoHelpfull: Yes(0) No(34)
- Please Give correct answer don't post wrong answer
- 6 years agoHelpfull: Yes(0) No(0)
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