How many ways can 4 prizes be given away to 3 boys, if each boy is eligible for all the prizes?

• The 4 prizes can be distributed to 3 boys in 3^4 =81ways
• 13 years agoHelpfull: Yes(38) No(19)
• 4prizes can be distributed to 3 boys in 4P3 ways(permutation) i.e.,4x3x2=24ways
• 13 years agoHelpfull: Yes(35) No(13)
• 15 ways.
  b1 b2 b3
  no of prize 4 0 0
  3 1 0
  3 0 1
  2 2 0
  2 0 2
  2 1 1
  1 3 0
  1 0 3
  1 2 1
  1 1 2
  0 4 0
  0 0 4
  0 3 1
  0 1 3
  0 2 2
  
• 12 years agoHelpfull: Yes(7) No(9)
• For the first time aprize can be any one of the 4. once a prize is given away remaining 3 prizes can be given away in 3c2 ways to the remaining two people.So each prize has 3c2 i.e. 6 ways of giving associated with it .So for 4 prizes total no of ways =6*6*6*6=6^4 ways.
• 12 years agoHelpfull: Yes(3) No(7)
• Let the 3 boys be B1, B2, B3 and 4 prizes be P1, P2, P3 and P4.
  
  Now B1 is eligible to receive any of the 4 available prizes (so 4 ways)
  B2 will receive prize from rest 3 available prizes(so 3 ways)
  B3 will receive his prize from the rest 2 prizes available(so 2 ways)
  
  Finally B4 will receive the the last remaining prize (so 1 way)
  So total ways would be: 4*3*2*1=24 Ways
  
  Hence, the 4 prizes can be distributed in 24 ways.
  
• 8 years agoHelpfull: Yes(2) No(1)
• first boy would get one prize from 4 available prizes,
  second boy would get one prize from remaining 3 available prizes,
  third boy would get one prize from remaining 2 available prizes,
  So 4*3*2=36
  
  
• 13 years agoHelpfull: Yes(1) No(20)
• (n+r-1)C(r-1)=6C4= 15.
• 10 years agoHelpfull: Yes(1) No(1)
• correct answer?
• 8 years agoHelpfull: Yes(0) No(0)
• Each prize can be given to 3 boys
  
  no of ways= 3^4=81 ways(n^r where n=3 and r=4)
• 5 years agoHelpfull: Yes(0) No(0)
• Let the 3 boys be B1, B2, B3 and 4 prizes be P1, P2, P3 and P4
  Now B1 is eligible to receive any of the 4 available prizes (so 4 ways)
  B2 will receive prize from rest 3 available prizes(so 3 ways)
  B3 will receive his prize from the rest 2 prizes available(so 2 ways)
  So total ways would be: 4 × 3 × 2 × 1 = 24 Ways
  Hence, the 4 prizes can be distributed in 24 ways
• 5 years agoHelpfull: Yes(0) No(0)