How many 4 digit can be formed by using 2,3,4,5,6,7 only once divisible by 25
remember only once* divisible by??

A)40
B)12
C)20
D)24

• 25 and 75 both are divisible by 25 once.
  so for 25 as last two digits, no. of 4 digit number formed = 4*3*1*1 = 12
  and for 75 as last two digits , no. of 4 digits number formed = 4*3*1*1 = 12
  therefore , total number is 12+12 = 24
• 10 years agoHelpfull: Yes(24) No(2)
• unit place will be only 5. tens place will be 2 or 7 only to be exactly divisible by 25 only once.
  at hundred place=3 or 4 or 6. so there are total 3 ways and at thousand place there is only 2 ways.
  so total possibilities = 2*3*2*1 = 12
• 10 years agoHelpfull: Yes(19) No(17)
• units place= 5
  tens place= 2 or 7(as tens place must have 2 or 7 to be exactly divisible by 25)
  remaining places= 3 or 4 or 6 or one from 2/5
  so total numbers formed= 3*2*2*2*1=24
• 10 years agoHelpfull: Yes(18) No(10)
• 5+4+2+1=12
  
• 10 years agoHelpfull: Yes(8) No(6)
• 20 all 24 once 24-4
  
• 10 years agoHelpfull: Yes(3) No(0)
• repeation is nt allowed hence... _ _ _ _
  only divisivble if once is filled with 5
  ten,s will b filled with 4 ways
  similarly 100th posisition 3 ways n
  1000th 2 ways _ _ _ _ 2*3*4=24
  
• 9 years agoHelpfull: Yes(3) No(0)
• ans 12
  last two digit must be 25 to be divisible by 25.
  fix 2 and 5 and now we have 4 digit for rest of two places
  for hundred place 4 digit
  for thousand place 3 digit
  so total number of numbers=3*4=12
  
• 9 years agoHelpfull: Yes(3) No(1)
• the numbers which are divisible by 2 times by 25 is 625*7 and 625*9..so the answer is 72-2=70...previous one was incorrect..
• 10 years agoHelpfull: Yes(1) No(4)
• unit 2 place digit will be either 25 or 75 hence 2 ways
  4th place can be puted (6-2) ways means 4 ways
  3rd place can be puted as 3 ways
  so 4*3*2=24
• 9 years agoHelpfull: Yes(1) No(0)
• The condition that the number is only once divisible by 25 means that it is a multiple of 25 but not 25^2=625. Since we are restricted to using the digits 2,3,4,5,6,7, the four-digit number will only be divisible by 25 if the last two digits are 25or 75. From these, we must remove those multiples of 625 between 2000 and 8000 in which the only digits are 2,3,4,5,6,7. Those multiples are:
  
  2500,3125,3750,4375,5000,5625,6250,6875,7500
  
  Assuming digits cannot be repeated, you correctly found the number of four-digit numbers that are divisible by 25. However, 4375 is also a multiple of 625 in which the only digits used are in the set {2,3,4,5,6,7} and no digits are repeated. Therefore, there are 24−1=23 numbers that satisfy the given condition.
• 9 years agoHelpfull: Yes(1) No(0)
• the number of 4 digit numbers (inc 2,3,4,5,6,7) which are divisible by 25 is : 6 * 6* 2* 1
  and the numbers which are two times divisible by 25 are also 1 time divisible by 625..so these numbers are only 625*5 , 625 *7, 625 *9.. because other numbers are either contains 0 or contain the digits which does not include in the question... so answer is (6*6*2*1-3)=69
• 10 years agoHelpfull: Yes(0) No(8)
• first 4*3and 25
  second case 4*3 and 75
  therfore 12+12=24 numbera
• 10 years agoHelpfull: Yes(0) No(1)
• Ans :-option b correct
• 10 years agoHelpfull: Yes(0) No(0)
• 3*4*2*1=24
  
• 10 years agoHelpfull: Yes(0) No(0)
• **26 and **76
  4c2=6
  6+6=12
  ans 12
• 10 years agoHelpfull: Yes(0) No(0)
• kindly mention if repetition is allowed or not....
• 9 years agoHelpfull: Yes(0) No(0)
• 24 is the ans
• 9 years agoHelpfull: Yes(0) No(0)
• there are 4 positions _ _ _ _
  unit digit will be only 5 so = only 1 way
  tens place will be 2 0r 7 = 2 ways
  so one digit at unit place and one digit at tens place
  total remaining digits are 4
  so remaining two positions can be filled in 4*3 ways
  so answer is 4*3*2*1= 24
• 9 years agoHelpfull: Yes(0) No(0)
• at ones place 5 is fixed.
  case 1. _ _25
  in this case last two digit is fixed as 25.
  so we have 3,4,6,7 options for remaining place
  so no. of ways to fill first two place using 3,4,6, 7= 4*3=12
  
  case2. _ _ 75
  similarly in this case last two digit is fixed as 75.
  so no. of ways to fill remaining two place is 4*3=12
  
  final answer= case1 + case2 =12+12 =24
  
  D is the answer
• 9 years agoHelpfull: Yes(0) No(0)
• Last digit should be 5 so and tens digit can be either 2 or 7 so 2 ways and rest is 3*2*2=12
• 9 years agoHelpfull: Yes(0) No(1)