Elitmus Exam Numerical Ability Probability

a dice has first 6 prime number on its side. This dice is rolling 10 times then what is the probable sum of all chances??

option->forgotten but i remmembered all option between 50 to 70.

Read Solution (Total 5)

The first 6 prime numbers are :- 2, 3, 5, 7, 11, 13
So, if the dice is rolled once the probable sum would be :-
(2 + 3 + 5+ 7 + 11 + 13)/ 6 = 41/6
So, when the dice is rolled 10 times the probable sum would be 10 * (41/6) = 68.33
10 years agoHelpfull: Yes(35) No(2)

just a correction since, the sum can only be an integer value. Hence, answer can be anything 68 or 69
10 years agoHelpfull: Yes(3) No(0)
Please clearifie
9 years agoHelpfull: Yes(1) No(1)
as it is a prime number so the number will be 2,3,5,7,9,11
so total will be 41 and avg will be 41/6 and its is rolling 10 times so 41/6*10 comes nearly 68..
9 years agoHelpfull: Yes(1) No(8)
clarify :-p
9 years agoHelpfull: Yes(0) No(0)

Elitmus Other Question

How many 4 digit can be formed by using 2,3,4,5,6,7 only once divisible by 25
remember only once* divisible by??

A)40
B)12
C)20
D)24 Runy wants to meet williomson. She goes and used v km/hr to cover distance and reached there in t hr. If one day she used v km/hr for 30 minutes then reued speed to 2v/5 then she reached destinaon late by 45 minutes. She said to williamsom that if she used v km/hr for 45 minutes and then redued speed to 2v/5 then she reached here 30 minutes late by t. then find v?

1,) 45 2.) 60 3.) 90 4. ) 36