If a car starts from A towards B with some velocity. Due to some problem in the engine after traveling 30km, the car goes with 4/5 th of its actual velocity The car reaches B 45 min later to the actual time. If the car engine fails after traveling 45km, the car reaches the destination B 36min late to the actual time What is the initial velocity of car and what is the distance between A and B in km

• 25km/hr and 105 kms.
• 13 years agoHelpfull: Yes(15) No(15)
• Distance = 105 kilometers.. velocity- speed= 25 km/hour.....
• 10 years agoHelpfull: Yes(5) No(4)
• Ans. let x is distance from A to B
  and y is initial speed.
  30/y+(x-30)5/4y -x/y = 3/4
  => 4x-12y=120 ----(1).
  45/y + (x-45)5/4y -x/y=3/5
  => 5x-12y=225 -------(2).
  From equ (1) and equ (2) we will get.
  x=25 and y=105
  so initial speed is 25 km/hr
  and Distance From A to B is 105 km
• 7 years agoHelpfull: Yes(2) No(3)
• THis sum can be solved easily by propotionality
  the vilocity is 4/5 th of its actual so s1:s2 =5:4 then speed inversely propotion to time so time t1:t2=4:5
  the gap is 5-4 is 1 and train is 45 min late. so gap 1=45 so 45*4:45*5=180:225
  so original time taken after 30 km is 180 mint.
  now after 45 km by same process t1:t2=4:5 we already know and this time 36 mint late so
  4*36:5*36=144:180. so this time 144 mint is actual time.
  after 30 km 180 mint total after 45 144 minute. so common distance is 15km 45-30 and common time difference is 36 minut
  now speed=15/36 nd we have to convert in hour so devide by 60 and it will
  15*60/36=25km/hr
  now we know speed total time 180 minut =3 hr so 25*3=75 +30 km before distance cover =105.
  Its seems like hard but if u ill understand propotionalityy it can be solved in a minute.
• 6 years agoHelpfull: Yes(0) No(0)