Three years ago , the average age of A, B and C was 27 years and that of B and C, 5 years ago was 20 years. A’s present age is :
A) 30 yrs B) 35 yrs C) 40 yrs D)48 yrs

• Sum of the present ages of A, B and C = (27 x 3 + 3 x 3) years = 90 years.
  
  Sum of the present ages of B and C = (20 x 2 + 5 x 2) years = 50 years.
  
  A's present age = (90 - 50) years = 40 years.
• 12 years agoHelpfull: Yes(26) No(11)
• three years ago : ( a+b+c)/3 = 27 is average age .
  but, 5 years ago b=c=20 years
  then , 3 years ago b=c=22 years
  we can write (22+22 +a )/3=27 ,a = 37 years
  now , a's present age 37+3 = 40 years .
• 8 years agoHelpfull: Yes(7) No(3)
• what is the age of A's after 8 years!!!
• 11 years agoHelpfull: Yes(2) No(2)
• three years ago a+b+c=27 then
  five years ago b & c age = 20,20 then
  at three years ago (a+22+22)/=27 ...... then 37 age of a's then 37+ 3 = 40 years
• 9 years agoHelpfull: Yes(2) No(1)
• A+B+C present age is = 90 (27*3+3+3+3)
  B+C present age 50 (20*2+5+5)
  A present age = 90-50=40
• 6 years agoHelpfull: Yes(2) No(0)
• Three yeras ago, the average age A, B and C was 30 yeras, and that of B and C five yeras agowas 22 yeras .A's present age is
• 8 years agoHelpfull: Yes(1) No(0)
• 27*3+9 - 20*2+20 = 40
• 9 years agoHelpfull: Yes(0) No(0)
• The sum of three different even numbers is 64 .Which are greater than 17. One number which will certainly there be
• 8 years agoHelpfull: Yes(0) No(0)