If 15 men or 24 women or 36 boys can do a work in 12 says working 8 hours a day, how many men should work together with 12 women and 6 boys to do a piece of work in times the earlier one, in 30 days working 6 hours a day?

a)10
b)8
c)4
d)14

• 15 men or 24 women or 36 boys can do a work in 12 days working 8 hours a day
  => 15 * 12 * 8 man hours = 24 * 12 * 8 woman hours = 36 * 12 * 8 boy hours
  => 15 man hours = 24 woman hours = 36 boy hours
  => 5 man hours = 8 woman hours = 12 boy hours
  
  To do the piece of work in 2 14 times the earlier one, man hours required
  = 15 * 12 * 8 * 94
  
  If N men alone completes this work in 30 days working 6 hours a day,
  N * 30 * 6 = 15 * 12 * 8 * 94
  => N = 18
  It means, 18 men can complete the new work in 30 days working 6 hours a day
  
  Now get the rations
  1 woman = 58 man
  1 boy =512 man
  
  12 women and 6 boys = 12 * 58 + 6 * 512 = 10 men
  Additional men required = 18 - 10 = 8
  
  Required number of men = 8
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