In a certain office 1 3 of the workers are women 1 2 of the women are married and 1

Given 1/3 of workers are women ===>So 2/3 of workers are men.
(1/3)*(1/2)*(1/3)=1/18 have children in women
men= 2/3 of workers so,
2/3*(3/4)*(2/3)= 1/3 and 1/3 can be written as 7/18
Total workers having childern 6/18+1/18= 7/18
Workers not having children = 1- 7/18 ============> (18-7)/18 ==== 11/18 is the Answer
9 years agoHelpfull: Yes(1) No(0)
i think the option is b)
bcz in the above solution the number of men got married (with children) is given as x/3 but
= (2/3) of (3/4) i.e (2/3)*3/4 gives u (x/2) isn't it????
thn ans becomes b)4/9

i request admin to provide only the correct solution ..............plz
i toooo confused
10 years agoHelpfull: Yes(0) No(0)
LET US ASSUME TOTAL WORKERS ARE 90
(YOU CAN ASSUME ANY NUMBER HERE. IT WOULD BE EASIER IF U TAKE NUMBER WHICH IS DIVISIBLE BY 2 AND 3 HERE. SO CALCULATION IS EASIER..)

WOMEN MEN
1/3 OF TOTAL WOEKERS ARE WOMEN.SO WOMEN=30 REMAINING ARE MEN=60
1/2 ARE MARRIED IN WOMEN MARRIED=15 3/4 ARE MARRIED SO MARRIED MEN=54
1/3 HAVE CHILD SO 5 WOMEN HAVE CHILD 2/3 OF MARRIED MEN HAVE CHILD. SO MEN WITH CHILD=30

TOTAL WORKERS WITH CHILD=30 MEN+5 WOMEN= 35
REMANING WORKERS WITHOUT CHILD=90-35=55
THEIR RATIO=55/90=11/18

ANSWER=11/18(C)
10 years agoHelpfull: Yes(0) No(0)

In a certain office, 1 / 3 of the workers are women, 1 / 2 of the women are married and 1 / 3 of the married women have children. If 3 / 4 of the men are married and 2 / 3 of the married men have children, what part of workers are without children ?

a. 5 / 18
b. 4 / 9
c. 11 / 18
d. 17 / 36