One test tube contains some acid and another test tube contains an equal quantity of water. To prepare a solution, 20 grams of the acid is poured into the second test tube. Then two thirds of the so formed solution is poured from the second tube into the first. If the fluid in first test tube is four times that in the second, what quantity of water was taken initially ?

a. 40 grams
b. 60 grams
c. 80 grams
d. 100 grams

• 4[1/3(x+20)] = x+2/3(x+20) , 2/3(x+20)= x= x/3, x/3=40/3 , x=40
• 10 years agoHelpfull: Yes(1) No(4)