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Arithmetic
From a group of boys and girls, 15 girls leave. There are then left 2 boys for each girl. After this, 45 boys leave. There are then 5 girls for each boy. The number of girls in the beginning was :
a. 40
b. 43
c. 29
d. 50
Read Solution (Total 2)
-
- Let b= number of boys in the beginning
Let g= number of girls in the beginning
15 girls leave, so b+(g-15)
There are 2 boys for each girl, so b=2*(g-15)
Then 45 boys leave the group, so(b-45)+(g-15)
Now 5 girls for each boy
g-15=5*(b-45)
g-15=5b-225
5b=g+210
b= (g+210)/5
now substitute b=2*(g-15)
2g-30=(g+210)/5
10g-150=g+210
9g=360
g=40
The number of girls in the beginning was 40 (option a)
- 11 years agoHelpfull: Yes(4) No(0)
- by trial an error method..
if there were 40 gals if 15 leave na.. remaining 25 gals.. 2 boys for each gals..so 50 boys.45 leave na.. 5 boys remaining... in 25 gals%5 =5 gals for each 1 boy... so ans is 40 :) - 10 years agoHelpfull: Yes(0) No(0)
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