exam Maths Puzzle Numerical Ability

Find the length of JK when J is (-5, 4) and K is (3, 2).

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Someone please help! The length of a rectangle is 8 in. more than twice its width. If the perimeter of the rectangle is 64 in., find the width of the rectangle. Any help would be greatly appreciated. Given:

y=-(x-2)^2
y=-(x^2-4x+4)
y=-x^2+4x-4
y=-(x^2-4x+4)
y=-x^2+4x-4

I have the following, is it correct? Thanks!

Vertex: (2,0)

Axis of Sym = X=2

Y-intercept