exam
Maths Puzzle
Numerical Ability
Find the length of JK when J is (-5, 4) and K is (3, 2).
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Someone please help! The length of a rectangle is 8 in. more than twice its width. If the perimeter of the rectangle is 64 in., find the width of the rectangle. Any help would be greatly appreciated.
Given:
y=-(x-2)^2
y=-(x^2-4x+4)
y=-x^2+4x-4
y=-(x^2-4x+4)
y=-x^2+4x-4
I have the following, is it correct? Thanks!
Vertex: (2,0)
Axis of Sym = X=2
Y-intercept