exam Maths Puzzle Numerical Ability

Given:

y=-(x-2)^2
y=-(x^2-4x+4)
y=-x^2+4x-4
y=-(x^2-4x+4)
y=-x^2+4x-4

I have the following, is it correct? Thanks!

Vertex: (2,0)

Axis of Sym = X=2

Y-intercept

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exam Other Question

Find the length of JK when J is (-5, 4) and K is (3, 2). the problem is 14-(2q+5)= -2q+9