Five years ago, the average age of A, B, C and D was 45 years. With E joining them now, the average of all the five is 49 years. How old is E ?

a. 25 years
b. 40 years
c. 45 years
d. 64 years

• 45 is answer..
  five years ago age is 45..so we can change to present after 5 years every person has increase on year..so is becomes 50 ..
  soo,,50*4(persons)=200..
  after e is adding now avg is 49 so 49*5(persons)=245..
  e age is 245-200=45..
• 10 years agoHelpfull: Yes(10) No(0)
• a+b+c+d-(5*4)=45*4
  a+b+c+d=180+20=200
  a+b+c+d+e=245
  (200)+e=245
  e=45
  answer is c)
• 10 years agoHelpfull: Yes(5) No(0)
• A-5+B-5+C-5+D-5/4=45
  A+B+C+D=200
  A+B+C+D+E/5=49
  A+B+C+D+E=245
  E=245-200=45
• 9 years agoHelpfull: Yes(4) No(0)
• the average age of a,b,c,d after 5yrs is 45(bcs after 5yrs age of every person will be increased by 5,so average will be same )
  the total age=45*4=200
  now a+b+c+d+e=(49*5)=245
  then e=245-200=45years
• 10 years agoHelpfull: Yes(2) No(4)
• 45 is answer
  five years before (a-5 + b-5 + c-5 + d-5) / 4 = 45
  =>a+b+c+d = 200
  after "e" joined later(now) ---> (a+b+c+d+e)/5 = 49
  (a+b+c+d+e) = 245
  =>e= 245 - (a+b+c+d)
  e = 245 - 200
  e = 45
• 9 years agoHelpfull: Yes(1) No(0)
• (a+b+c+d)/4=45
  after 5 years: (a+b+c+d)/4=45+(20/4)
  (a+b+c+d)/4=50
  a+b+c+d=200
  now (a+b+c+d+e)/5=49
  (a+b+c+d)/5+e/5=49
  200/5+e/5=49
  40+e/5=49
  e/5=9
  e=45
  c)45
• 9 years agoHelpfull: Yes(1) No(0)
• c. 45 year
  5 year ago : a+b+c+d=4*45=180
  now : 180 + 5*4 + e =49*5 = 245
  e = 45
• 9 years agoHelpfull: Yes(1) No(0)
• answer is 65 years
  a+b+c+d=45*4=180
  now a+b+c+d+e=49*5=245
  from above 2 equation
  180+e=245
  e=65 yrs
  i think
• 10 years agoHelpfull: Yes(0) No(5)
• answer is 65 years
  same as above asnswer
  
• 10 years agoHelpfull: Yes(0) No(4)
• average age of 4 person is 45
  so total age of 4 persons is= 4*45=180
  after joining E persons become 45 and average becomes 49.
  so total age of 5 persons become 5*49=245
  Therefore, the age of E becomes= 245-190=65 years
  
• 10 years agoHelpfull: Yes(0) No(3)
• A+B+C+D=45*4
  SUM=180
  A+B+C+D+E=49*5
  NEW SUM=245
  NEW SUM-SUM=65=AGE OF E
• 10 years agoHelpfull: Yes(0) No(2)
• 49*5-(45*4+5*4)=45
  
• 9 years agoHelpfull: Yes(0) No(0)
• 5 years ago.......
  A+B+C+D=45*4=180;
  AFTER FIVE YEARS....
  A+B+C+D=180+20=200;
  NOW
  A+B+C+D+E=49*5=245
  200+E=245
  E=45;
• 9 years agoHelpfull: Yes(0) No(0)
• sum of age of first 4 before 5 years= 45*4=180
  increase in age of 4 in 5 years=4*5=20
  total age of 4 after 5 year=180+20=200
  age after joining of e=49*5=245
  age of e=(age of four-age of all 5)=245-200=45
• 8 years agoHelpfull: Yes(0) No(0)
• a+b+c+d-(5*4)=45*4
  a+b+c+d=180+20=200
  a+b+c+d+e=245
  (200)+e=245
  e=45
  answer is c)
• 7 years agoHelpfull: Yes(0) No(0)