The population of a town increases 4% annually but is decreased by emigration annually to the extent of (1/2)%. What will be the increase percent in 3 years ?

a. 9.8
b. 10
c. 10.5
d. 10.8

• option(D)
  let initial population be 100.
  after the end of year 1 population=100+3.5=103.5
  after the end of year 2 population=103.5+103.5*3.5/100=107.12
  after the end of year 3 population=107+107*3.5/100=110.8
  
  so increase percentage =110.8-100=10.8
• 9 years agoHelpfull: Yes(8) No(0)
• Net % change= a+b+(ab/100) = 4-1/2-[(4*1/2)/100] = 348/100 = 3.48
  In 1 year % increase is 3.48%
  So, in 3 years % increase will be 3*3.48= 10.44 = 10.5% (c)
• 10 years agoHelpfull: Yes(7) No(2)
• Annually increased 4%
  annually decreased 1/2%
  
  So after 3 years Annually increased 4%*3= 12%
  Annually decreased 1/2% *3 = 1.5%
  
  So answer is 12% - 1.5 % = 10.5%
• 9 years agoHelpfull: Yes(7) No(1)
• p(1+r/100)^n
  r=3.5
  n=3
  p=population
  ans 10.8
• 9 years agoHelpfull: Yes(1) No(0)
• Net % change= a+b+(ab/100) = 4-1/2-[(4*1/2)/100] = 348/100 = 3.48
  so net change is 3.48
  so from the formula A(1+r/100)^n {population after n year}
  total population= 1.108A, so increse=10.8
  
  
• 9 years agoHelpfull: Yes(1) No(0)
• D
  It is because on solving I got that
  
• 10 years agoHelpfull: Yes(0) No(4)
• plz give the complete solution
• 10 years agoHelpfull: Yes(0) No(1)
• 10.8 is the correct answer
• 9 years agoHelpfull: Yes(0) No(0)
• ans: 10.5
  {
  let x=total popu. ,so
  x+3[4%-(1/2%)], solve only 2nd part which willl giv u ..... 10.5%
  }
• 9 years agoHelpfull: Yes(0) No(0)
• ans is 10.8
  
• 9 years agoHelpfull: Yes(0) No(0)