A is 50 as efficient as B C does half the work done by A amp B together If C

let B can do the work in x days.
A can do the work in 2x days.
let e b total work.
work done by A in 1 day=a/x
work done by B in 1 day=a/2x
if both A&B together do the work then 1day work =a/x+a/2x=3a/2x
no. of days in which both A&B will complete=1/(3a/2x)*a=2x/3
2*2x/3=40
x=30. individual time(A=60,B=30,C=40)
now work done by A B C in 1 day =a/30+a/40+a/60=3a/40
days taken to do a work by A B C=a/3a/40=40/3
9 years agoHelpfull: Yes(2) No(1)
(A's 1 day work):(b's 1 day work)=150:100=3:2
let A and B one day work is 3x:2x
then c's one day work is 3x+2x/2=5x/2
therefore 5x/2=1/40=1/100
so A's 1 day work=3/100
B's 1day work is 2/100=1/50
c's 1 day work is 1/40
adding three we get 15/200=3/40
so the work done by A,B,c is 40/3
13 1/3
8 years agoHelpfull: Yes(2) No(1)
A 6
B 4
C 10 X 40 =400
A+B+c 20 X K = 400
K=20. SO 20 DAYS TO COMPLETE ALL DAYS
9 years agoHelpfull: Yes(0) No(7)

A is 50% as efficient as B. C does half the work done by A & B together. If C alone does the work n 40 days, then A,B and C together can do the work in?