A alone can complete a work in 16 days and B alone can complete the same in 12 days. Starting with A, they work on alternate days. The total work will be completed in how many days?

• A can do in 1/16
  B can do in 1/12
  
  A+B=1/16+1/12
  3+4/48
  7/48
  now A+B can do the work in 48/7 days or we can say approx. 7days
• 11 years agoHelpfull: Yes(2) No(4)
• A's 1 day work=100/16=6.25%
  B's 1 day work=100/12=8.33%
  (A+B)'s 1 day work=(6.25+8.33)%
  =14.58%
  after 6 days it will be=14.58*6=87.48%, means alternate work for 12 days(1st day work of A and 2nd work of B=(A+B)'s 1 day work)
  after 12 days work left=12.52%
  in 13th day A's work=6.25%
  12.52%-6.25%=6.27% left
  in 14th day B will complete the work
• 9 years agoHelpfull: Yes(1) No(0)
• the ans will be 13(3/4)
• 9 years agoHelpfull: Yes(1) No(0)
• A+B=1/16+1/12
  3+4/48
  7/48(A and B n 2 days)
  (A+B) 2 dAYS*6=(7/48)*6
  =42/48
  Remaining=1-(42/48)
  =1/8(this is A 'S turn)
  ans:12 1/2 days (totally)
  
  
• 10 years agoHelpfull: Yes(0) No(0)
• In one day, A's work=1/16
  " " ", B's work=1/12
  A's and B's total work in 1 day=1/16 + 1/12 =7/48.
  But they work on alternate days..So 7/48 amount of work is completed by A and B alternatively in 2 days.
  Therefore,Total work will be completed by A and B in 2*(48/7)=14 days(approx.).
• 9 years agoHelpfull: Yes(0) No(0)