Seven men can complete a work in 12 days. They started the work and after 5 days, two men left. In how many days will the work be completed by the remaining men?
(A) 5 (B) 6 (C ) 7 (D) 8 (E) none

• 7 men 1 day's work will be 1 / 12
  1 man 1 day work will be 1 / (12*7) = 1 / 84
  7 men 5 days work will be 5 / 12, so remaning work will be (1- 5/ 12) = 7 / 12
  5 men 1 day work will be 5 / 84
  7/12 work is done by them in (84/5)*(7/12)=9 4/5 days
  
• 10 years agoHelpfull: Yes(4) No(0)
• 1 men 1 day work=1/7*12=1/84
  7 men 5 day work = (7*5)/12*7=5/12
  remaining work=(1-5/12)=7/12
  5 men 1 day work=5/12*7=5/84
  7/12 work will be done by them in=(7/12)*(84/5)=49/5= 9 4/5 days..
  
• 10 years agoHelpfull: Yes(2) No(0)
• 7 men 1 day's work will be 1 / 12
  1 man 1 day work will be 1 / (12*7) = 1 / 84
  7 men 5 days work will be 5 / 12, so remaning work will be (1- 5/ 12) = 7 / 12
  5 men 1 day work will be 5 / 84
  7/12 work is done by them in (84/5)*(7/12)= 49/5 days
• 5 years agoHelpfull: Yes(1) No(0)