A is 80 % more efficient than B who is 60% more efficient than C. A takes 40 days less than B to complete a work. A starts the work and works for 25 days and then B takes over. B then work for the next 30 days and then stops. In how much more time can C complete the remaining work?

• Let assume C's efficiency=100
  Then B's efficiency=100+60%of100=160
  Then A's efficiency=160+80%of160=288
  
  Ratio of efficiency_____
  A:B:C
  72:40:25
  
  Then ratio of time______
  A:B:C
  1/72:1/40:1/25=25:45:72
  
  A takes 20 days less than B (according to time ratio)
  A takes 40 days less than B (given in question)
  So
  A can complete the work in=25×40/20=50 days
  B can complete the work in=45×40/20=90 days
  C can complete the work in=72×40/20=144 days
  Let assume total work is 1
  A's work+B's work+C's work=1
  25/50 + 30/90 + C/144=1
  1/2 + 1/3 + C/144=1
  C=24 days ans.
• 9 years agoHelpfull: Yes(2) No(4)