There are two box, one containing 10 red balls and the other containing 10 green balls. You are allowed to move the balls between the boxes so that when you choose a box at random and a ball at random from the chosen box, the probability of getting a red ball is maximized. This maximum probability is
a) 1/2
b) 14/19
c) 37/38
d) 3/4

• 14/19
  1/2 + 1/2 *9/19 = 1/2(1+9/19) =(1/2 )*(28/19) = 14/19
• 14 years agoHelpfull: Yes(25) No(3)
• Answer : (a)1/2
  
  Now the only possibility is shifting 5 balls from one box to another giving a probability of 1/2. If more than 5 balls are shifted from any of the boxes then the probability of finding red balls will be minimized in the one of the boxes while increased in the other.
• 14 years agoHelpfull: Yes(6) No(18)
• 14/ 19
  
• 14 years agoHelpfull: Yes(5) No(3)
• 14/19
  it is solved prviously plz check it
• 14 years agoHelpfull: Yes(4) No(3)
• ((1/2)*1)+((1/2)*(9/19))=(*14/19)
• 14 years agoHelpfull: Yes(3) No(1)
• 14/19
• 14 years agoHelpfull: Yes(1) No(4)