In a 100 m race, A can beat B by 25 m and B can beat C by 4 m. In the same race, A can beat C by:

A. 21 m B. 26 m
C. 28 m D. 29 m

• Ans. C- 28 m
  When A run 100m, B will run 975m.
  Distance ratio of A:B= 100:75= 4:3
  When B Run 100m, C will run 96m.
  Now B:C=100:96= 25/24
  now A:C=A:B*B:C
  4/3*25/24=25/18
  now A:C= 25*4/18*4= 100/72
  So when A run 100m, C will run 72 and A will beat C by =(100-72) = 28 m.
  
• 9 years agoHelpfull: Yes(26) No(2)
• A : B = 100 : 75
  
  B : C = 100 : 96.
  
  A:C=(a/b * a/c) = (100/75 * 100/96)=72
  c= (100-72) = 28m.
• 9 years agoHelpfull: Yes(6) No(5)
• a b c
  100 75
  100 96
  ________________________________
  100 75 ?
  
  (75*96)/100=72
  S0 c=72
  
  100-72=28
  C)28
• 10 years agoHelpfull: Yes(1) No(1)
• A : B = 100 : 75
  
  B : C = 100 : 96.
  
  A : C = A x B = 100 x 100 = 100 = 100 : 72.
  B C 75 96 72
  A beats C by (100 - 72) m = 28 m.
• 9 years agoHelpfull: Yes(0) No(1)
• c=a+b-ab/l
  c=25+4-25*4/100
  c+29-1
  c+28m
• 9 years agoHelpfull: Yes(0) No(0)
• 
  
  A : B = 100 : 75
  
  B : C = 100 : 96.
  
  A : C = A x B = 100 x 100 = 100 = 100 : 72.
  B C 75 96 72
  
  A beats C by (100 - 72) m = 28 m.
  
• 7 years agoHelpfull: Yes(0) No(0)
• A:B=100:75 =>4:3
  B:C=100:96 =>25:24
  since they are in continued proportion,
  we can write it as
  A:B:C=100:75:72 (4*25:3*25::25*4:24*4)
  so,
  A:C=100:72
  A can beat C by 100-72=28m
  
• 7 years agoHelpfull: Yes(0) No(0)